This lecture is part of the MEEP curriculum on General Chemistry. Information about Project MEEP and other General Chemistry lectures are available below.
How can intramolecular interactions explain intermolecular forces?
What types of IMFs are there and how are they different from each other?
How can IMFs help us predict states of matter (phases)?
Lecture Content (Part 1)
Welcome to Chapter 3! In the previous chapter (Chapter 2 – Intramolecular Interactions and Representations), we talked about interactions within the molecule itself. Those intramolecular interactions mostly amount to the following concepts:
Electron configurations and periodic table trends
Different types of bonding (ionic, covalent, and metallic)
Covalent bonding (Lewis structures, VSEPR, molecular geometry, and resonance)
Visualization of different molecules using online resources
In this new chapter, we zoom out our perspective. Rather than looking at what happens within a molecule, we look at what happens between molecules. In other words, we will focus on intermolecular interactions.
Of course, intramolecular interactions usually affect intermolecular interactions. Consequently, we will still be discussing Chapter 2 material in this chapter.
So, we will present Chapter 3 materials using the following outline.
Firstly, we discuss different types of intermolecular interactions (intermolecular forces, or “IMF” for short). Depending on the IMFs, compounds can be in different states (gases, liquids, and solids).
Secondly, we will discuss how gases behave.
Thirdly, we will discuss how liquids and solids behave.
Lastly, we will discuss how solutions and colloids behave.
Using this outline, we will be exploring intermolecular forces this lecture.
Update: Toolbar on the bottom right
The equation sheet is updated to reflect equations introduced in Chapter 1.
The Source of Intermolecular Forces
Let’s first talk about what intermolecular forces are.
An intermolecular force (IMF) is the force that mediates interaction between molecules, including the electromagnetic forces of attraction or repulsion which act between atoms and other types of neighbouring particles (e.g. atoms or ions).
Intermolecular forces are weak relative to intramolecular forces – the forces which hold a molecule together. For example, the covalent bond, involving sharing electron pairs between atoms, is much stronger than the forces present between neighboring molecules.
So, here comes the question: What causes intermolecular forces? What causes molecules to interact with each other? The answer lies within the intramolecular compositions of a molecule.
Dipole Moments
Let’s focus back to what happens within a molecule. A molecule’s intramolecular properties can be described by electron movements, as discussed in Lectures 6 (Chemical Bonding and Electron Movements) and 7 (Lewis Structures and Molecular Geometry). Using this as a starting point, let’s considering the following logic.
Suppose an atom of a molecule is exceptionally good at retaining electrons around itself compared to the surrounding atoms. In other words, that atom has high electronegativity $\chi$.
As a result, that atom would have more electrons surrounding it compared to the surrounding atoms.
That atom, in the end, will obtain a partial negative charge $\delta^-$, while the surrounding atoms will obtain a partial positive charge $\delta^+$.
Now, let’s zoom out to look at the molecule – one part of the molecule will be slightly negative $\delta^-$, while another part of the molecule will be slightly positive $\delta^+$.
So, if we put a lot of the same molecules together, the molecules should align themselves such that the $\delta^-$ and $\delta^+$ are close together between 2 molecules.
That attraction between opposite partial charges ($\delta^-$ and $\delta^+$) is what we call an IMF.
Let’s look at an example visualization below.
In our logic above, we stumbled upon a new concept called the dipole moment.
The dipole moment is a measure of the separation of positive and negative electrical charges within a system.
We can actually express a dipole moment on a molecule by drawing an arrow pointing from the $\delta^+$ atom to the $\delta^-$ atom.
We can also add up individual dipole moments to get a net dipole moment, since a dipole moment is a vector (magnitude + direction).
Using the same molecule as the visualization example, we can draw out individual dipole moments and calculate the net dipole moment of this molecule.
As we can see, the water molecule has a net dipole moment pointing from the hydrogen atoms to the oxygen atom. This concept explains why molecules align in a certain way.
Polarity
Individual dipole moments and the net dipole moment both help us understand the concept of polarity – a property of a molecule.
Polarity is a separation of electric charge leading to a molecule or its chemical groups having a dipole moment, with a negatively charged end and a positively charged end.
Bond polarity specifically refers to the polarity of the covalent bond of interest. It is caused by electronegativity differences $\Delta\chi$ between 2 atoms.
Molecular polarity specifically refers to the polarity of the entire molecule. It can be determined by calculating the net dipole moment.
We can have a non-polar molecule (molecular polarity) connected by polar covalent bonds (bond polarity).
Just to clarify, polarity and dipole moments are different concepts.
An individual dipole moment is a vector pointing from $\delta^+$ to $\delta^-$. It is caused by bond polarity.
A net dipole moment is a vector that can be calculated by adding up all the individual dipole moments in the same molecule.
Bond polarity is a property of a covalent bond that is caused by electronegativity differences between 2 atoms.
Molecular polarity is a property of the entire molecule that can be determined by looking at the net dipole moment.
To summarize, $\Delta\chi$ between 2 atoms causes bond polarity, which causes individual dipole moments that can add up to a net dipole moment, which can help determine the molecular polarity.
Here, the concept of “bond polarity” should ring a faint bell in our minds. Recall in Lecture 6 (Chemical Bonding and Electron Movements), we talked about how electronegativity differences can help us predict bond formation.
Review of Lecture 6 – $\Delta\chi$ and Bond Formations
Directly quoted from Lecture 6:
Electronegativity differences $\Delta\chi$ is one of the many factors that influence bond formation. Other factors include chemical and physical properties. However, for most cases, just looking at $\Delta\chi$ is sufficient to predict bond formation.
If $\Delta\chi > 1.8$, it generally forms an ionic bond.
If $\Delta\chi < 0.4$, it generally forms a pure covalent bond.
If $\Delta\chi$ is in between, it generally forms a polar covalent bond.
Again, there are exceptions to the boundaries, so don’t just plug-and-chug.
Electronegativity difference can more or less accurately determine bond type – ionic or covalent. Again, the boundaries are not consistent throughout sources.
So, having a polar covalent bond is the same thing as saying the covalent bond is polar. This sounds simple enough but it’s always nice to connect concepts together.
We will look at some examples below.
Polarity Examples: Polarity and Molecular Symmetry
Example 1: $CH_4$
Example 2: $CO_2$
For example 1, the electronegativity difference is: $\Delta\chi = 2.55 – 2.20 = 0.35$. The $\Delta\chi$ is small enough that we can assume minimum bond polarity. Since there is minimum bond polarity, there is essentially barely any dipole moment. Thus, there is no net dipole moment. Consequently, the molecule is not polar.
For example 2, the electronegativity difference is: $\Delta\chi = 3.44 – 2.55 = 0.89$. The $\Delta\chi$ is large enough that we can conclude that the CO covalent bonds are both polar, creating individual dipole moments that point from C to O. However, since the dipole moments are pointing in opposite directions, they cancel each other out, creating no net dipole moment. Consequently, the molecule is nonpolar.
Example 3: $CH_3F$
Example 4: $CF_4$
For example 3, the electronegativity difference between CH is negligible. The electronegativity difference between CF, on the other hand, is: $\Delta\chi = 3.98 – 2.55 = 1.43$, resulting in a highly polar CF covalent bond, creating a strong dipole moment pointing from C to F. Since that is the only non-trivial dipole moment, we have a net dipole moment pointing in the same direction. Since we have a net dipole moment, we can determine that this molecule is polar.
For example 4, similarly, we have strong individual dipole moments from the highly polar CF covalent bonds. However, if we add up those individual dipole moments, the net dipole moment is actually 0 because they all cancel each other out. As a result, this molecule is nonpolar.
Example 5: $HCN$
Example 6: $HCl$
For example 5, we have a nonpolar CH covalent bond and a polar CN covalent bond ($\Delta\chi = 3.04 – 2.55 = 0.49$), creating an individual dipole moment pointing from C to N. Since the CN dipole moment is the only non-trivial dipole moment in this molecule, it would also be our net dipole moment, making this molecule polar.
For example 6, we have a highly polar HCl covalent bond with a $\Delta\chi$ of 0.96, creating an individual dipole moment pointing from H to Cl. The net dipole moment will be the same, making this molecule polar.
Here is a nice table to summarize our examples.
Example
$\Delta\chi$
Bond
Individual DM
Net DM
Molecule
$CH_4$
CH: 0.35
CH: nonpolar
None/Negligible
None/Negligible
Nonpolar
$CO_2$
CO: 0.89
CO: polar
$C\rightarrow O$
Canceled out due to symmetry
Nonpolar
$CH_3F$
CH: 0.35 CF: 1.43
CH: nonpolar CF: polar
$C\rightarrow F$
$C\rightarrow F$
Polar
$CF_4$
CF: 1.43
CF: polar
$C\rightarrow F$
Canceled out due to symmetry
Nonpolar
$HCN$
CH: 0.35 CN: 0.49
CH: nonpolar CN: polar enough
$C\rightarrow N$
$C\rightarrow N$
Polar
$HCl$
HCl: 0.96
HCl: polar
$H\rightarrow Cl$
$H\rightarrow Cl$
Polar
DM denotes “dipole moment” for this table only because space is running out. We don’t abbreviate dipole moments as “DM”.
If there are still confusions, don’t worry, there are plenty of examples and exercises coming up at the end of this lecture and in the worksheet.
A concept we introduced in the examples that would significantly help us in determining molecular polarity is the symmetry of a molecule. If the molecule is symmetrical, individual dipole moments can cancel each other out.
Types of Intermolecular Forces
We will introduce those forces from weakest to strongest. We can also predict IMFs by looking at the polarity of the molecules involved. Understandably, IMFs between nonpolar molecules would be weak, while IMFs between polar molecules would be strong.
So, the types of IMFs will be roughly categorized by molecules of different polarity.
Nonpolar molecules and nonpolar molecules
Nonpolar molecules and polar molecules
Polar molecules and polar molecules
Dispersion Forces
This IMF is found between nonpolar molecules. Since nonpolar molecules don’t have net dipole moments, how can molecules attract each other? The answer lies in spontaneous dipoles.
Spontaneous individual dipole moments can spawn out of pure chance by electron movements – the electrons just happen to move into a position such that a separation of charge is present. Consequently, molecules can develop spontaneous net dipoles.
We can imagine spontaneous dipoles as “accidental” dipoles. Spontaneous dipoles also go by the term “instantaneous dipoles”.
Now, we have a dipole for one molecule, but IMFs need 2 molecules with dipoles to work. Here, we introduce another concept – induced dipoles.
Induced dipoles in a molecule (1) are net dipole moments that are induced by molecules (2) with existing dipole moments close to it (1) because existing dipole moments (2) have partial charges, aligning the original molecule’s (1) electrons to have favorable interactions with the other molecules (2).
This spontaneous dipole – induced dipole (molecule A has a spontaneous dipole, while molecule B has an induced dipole) IMF is called dispersion forces (also known as London dispersion forces in honor of the scientist Fritz London, not the city). We’ll abbreviate it as “LDF”. Let’s look at a visualization of LDFs.
As we can see, because this IMF relies on spontaneous movements, which implies that:
Dispersion forces can spontaneously appear and spontaneously disappear.
Dispersion forces are present in every type of molecule, regardless of polarity.
Dispersion forces are very weak.
The following molecules have purely LDFs between themselves because they are all nonpolar.
$CH_4$
$C_2H_6$
$Ne$
$CF_4$
Nonpolar because of tetrahedral symmetry
$SF_6$
Nonpolar because of octahedral symmetry
$C_8H_{18}$
The following molecules experience predominantly LDFs between them because they are largely nonpolar. Those molecules do experience other IMFs but LDFs are the main stabilizing IMF because of sheer size. (Note: lone pairs are not included in the Lewis structures for the structures below)
Beta-carotene ($C_{40}H_{56}$)
Tristearin ($C_{57}H_{110}O_6$)
Vitamin E ($C_{29}H_{50}O_2$)
Corticosterone ($C_{21}H_{30}O_4$)
Again, these are biochemical molecules with important functions.
Beta-carotene is a precursor to vitamin A, which has functions including growth during embryo development, maintaining the immune system, and healthy vision.
Tristearin is a type of triacylglycerol – a main constituent of human body fat. It is heavily involved in efficient energy storage.
Vitamin E is a group of compounds that help target reactive oxygen species (ROS). Recall that ROS contains radicals, which are highly reactive and can cause damage to our DNA.
Corticosterone mainly exist as an intermediate for the synthesis of aldosterone – a compound playing a central role in the homeostatic regulation of blood pressure, plasma sodium (Na+), and potassium (K+) levels.
As we can see, despite having oxygen (a fairly electronegative atom) in the structure, possibly introducing dipole moments, the main IMF of those molecules are LDFs because of the sheer size of the nonpolar regions. Of course, other IMFs exist in those molecules, such as dipole-dipole interactions and hydrogen bonds, which we will discuss soon.
Dipole – Induced Dipole Interactions
This type of interaction is tailored to interactions between polar and nonpolar molecules. We will abbreviate it as “D-ID” for this class.
The “dipole” part of this IMF is easy to understand – it comes from the polar molecule, which itself has a dipole moment. The “induced dipole” part of this IMF should also be easy to understand. Since we have an existing dipole from the polar molecule, it can influence a nonpolar molecule next to it to have an electron distribution such that there is a dipole. In other words:
Existing dipoles can induce dipoles from nonpolar molecules.
Here are some examples where D-ID interactions are the predominant IMF. Note that in all of the examples below, LDFs are also present. However, LDFs are not the predominant IMF here.
D: Ethanol ($C_2H_6O$) ID: Iodine ($I_2$)
D: Chloroform ($CHCl_3$) ID: Methane ($CH_4$)
D: Acetone ($C_3H_6O$) ID: Benzene ($C_6H_6$)
D: Water ($H_2O$) ID: Oxygen ($O_2$)
For the examples above, try to answer the following questions:
Which molecule has existing dipoles? (i.e., which molecule is polar?)
Which molecule has induced dipoles? (i.e., which molecule is nonpolar?)
For the molecule with existing dipoles, what is the direction of its net dipole moment?
For the molecule with induced dipoles, how is it nonpolar?
Is it because it has no obvious individual dipole moments, or…
Is it because molecular symmetry canceled out the individual dipole moments?
Dipole – Dipole Interactions
This type of interaction is tailored to interactions between polar molecules. We will abbreviate it as “D-D” for this class. Here are some examples with D-D interactions being the predominant IMF. Note that for all of the examples below, they all contain LDF and D-ID interactions.
DMSO ($C_2H_6OS$)
Hydrochloric Acid ($HCl$)
Formaldehyde ($CH_2O$)
Propanal ($C_3H_6O$)
Similarly, for those molecules, try to answer the following questions.
Is the molecule polar? (The answer should be yes for all of them)
If the molecule is polar, where is the direction of the net dipole moment?
Hydrogen Bonding
Hydrogen bonding is important. Hydrogen bonding is very important. Hydrogen bonding is extremely important.
Hydrogen bonding is considered as a special case of dipole-dipole (D-D) interactions. We may abbreviate it as “H-bonding”.
Hydrogen bonding should look like the following:
$$R-Dn\text{-}H \cdots Ac-R$$
where:
$Dn$ denotes hydrogen bond donator, because they contain the hydrogen
$H$ denotes the hydrogen atom
$\cdots$ denotes the hydrogen bond IMF
$Ac$ denotes the hydrogen bond acceptor
$R$ denotes unimportant parts of the molecule
$Dn$ and $Ac$ need to be the elements “N”, “O”, and “F” for this dipole-dipole interaction to be considered as hydrogen bonding.
The reason that it is important is because:
It is stronger than dipole-dipole interactions because it involves N, O, F – the most electronegative elements – and H.
It is everywhere in biochemistry, considering water $H_2O$ is the universal solvent.
Hydrogen bond is an IMF. Hydrogen bonds are different from ionic/covalent/metallic bonds.
Using this definition, we can look at the following examples with H-bonding as the predominant IMF. (As usual, they all contain LDFs and D-IDs)
Because formaldehyde does not have hydrogen atoms directly attached to N, O, or F, it can only be a hydrogen bond acceptor. As a result, it needs a hydrogen bond donator (Dn-H where Dn = N, O, or F).
Since hydrogen bonding is very important, we have to talk about medical/biochemical applications of hydrogen bonding. Also, the molecules get pretty big in those examples, so a molecule can have both hydrogen bond donators and acceptors. For example, we can look at carboxylic acid ($HCO_2H$).
For the oxygen at the top, since it does not have a hydrogen atom directly attached to it, it can only be a hydrogen bond acceptor. For the oxygen to the right, it can be both a donator and an acceptor.
Note: In the graphs below, H-bonds are in dashed lines, hydrogen bond acceptors are highlighted, and lone pairs are not included.
Adenine-Thymine (AT) base pair in DNA
Cytosine-Guanine (CG) base pair in DNA
Parallel beta-sheets in proteins
Antiparallel beta-sheets in proteins
The middle structure is flipped horizontally.
For the first 2 examples, we have AT and CG base pairings – the golden rule in DNA structure. Since AT has 2 hydrogen bonds while CG has 3 hydrogen bonds, CG pairings are typically stronger than AT pairings.
For the next 2 examples, we have secondary protein structures called beta sheets, which are important in protein conformations (shapes). Similarly, they are stabilized by hydrogen bonds.
Other examples include things like structures dissolving in water, like acetone dissolving in water, aspirin dissolving in water, ammonia dissolving in water, etc.
Ion – Dipole Interactions
Ion-dipole interactions are for ions and polar molecules. They are even stronger than hydrogen bonds, because rather than having partial charges attracting each other, actual charges are involved. We’ll abbreviate this as “Ion-D”. The most textbook example of this is table salt ($NaCl$) dissolving in water.
$$NaCl (s) \rightarrow Na^+ (aq) + Cl^- (aq)$$
Since $Na^+$ is positively charged, water will align in a way such that the oxygen (partial negative) will point towards $Na^+$.
Since $Cl^-$ is negatively charged, water will align in a way such that the hydrogen (partial positive) will point towards $Cl^-$.
As long as we see ions and polar molecules, we can usually assume that ion-dipole interactions are predominant.
We can keep going on and have ion-ion interactions, but at that point, it’s the same thing as ionic bonds.
Summary
We introduced 5 types of IMFs – 4 main IMFs and 1 special IMF – listed in increasing strength below.
Dispersion forces (LDF)
Dipole – induced dipole (D-ID)
Dipole – dipole (D-D)
Special case: Hydrogen bond (H-bond)
Ion – dipole (Ion-D)
IMF
Molecules
Dipoles
Strength
Examples
LDF
Nonpolar – Nonpolar
Spontaneous Dipole – Induced Dipole
Weakest
$CH_4$
D-ID
Polar – Nonpolar
Existing Dipole – Induced Dipole
Weaker
$I_2$ in $C_2H_6O$
D-D
Polar – Polar
Existing Dipole – Existing Dipole
Strong
$CH_2O$
H-bond (Special D-D)
Polar – Polar (Dn-H … Ac) Dn, Ac = N/O/F
Existing Dipole – Existing Dipole
Stronger
$H_2O$
Ion-D
Ion – Polar
Ion – Existing Dipole
Strongest
$Na^+$ in $H_2O$
LDF, H-bonding, and Ion-D are pretty important as we go on into biochemistry.
Ideally, we should memorize this by heart. Also, here are some terms we should clarify.
The strongest and predominant IMF could be different in a sample. For example, let’s consider the molecule tristearin – a type of triacylglycerol.
Diagram of tristearin. Click to enlarge diagram!
The IMFs present in this molecule are:
LDF
D-ID
D-D
The strongest IMF in this molecule is D-D. However, the predominant IMF in this molecule is LDF because there is an overwhelming nonpolar region presence in this molecule – the D-D interactions is incomparable to the sheer amounts of LDFs from the nonpolar regions of the molecule.
Of course, the exact boundary of “overwhelmingness” is very blurry. So, as long as we can identify and acknowledge that “oh, there should be a strong LDF presence”, we should be fine. Also, if LDF is the predominant IMF in a molecule in a quiz/test problem, it should be very obvious.
Intermolecular Forces in Phase Transitions
We will talk more about the thermodynamics behind phase transitions in Unit 2. For now, we will be brief about it.
A solid has a stable, definite shape, and a definite volume. Solids can only change their shape by an outside force, as when broken or cut.
A liquid is a nearly incompressible fluid that conforms to the shape of its container but retains a (nearly) constant volume independent of pressure.
A gas is a compressible fluid. Not only will a gas conform to the shape of its container but it will also expand to fill the container.
Also, recall the graph regarding phase transitions.
Melting: solid to liquid
Freezing: liquid to solid
Vaporization: liquid to gas
Condensation: gas to liquid
Sublimation: solid to gas
Deposition: gas to solid
Melting point is the temperature where solid becomes liquid or liquid becomes solid. Boiling point is the temperature where liquid becomes gas or gas becomes liquid.
We will focus on the following concepts in this section.
Comparatively, how do IMFs determine the state of matter? In other words, how do IMFs determine substances to be in solids, liquids, and gases?
Comparatively, how do IMFs influence the melting and boiling points of substances?
Before we go predicting phases, here are the basics.
Compounds in gas phase usually have comparatively weak IMFs. Weak IMFs mean low levels of intermolecular attraction, allowing gas molecules to flow freely.
Compounds in liquid phase usually have comparatively moderate IMFs. Moderate IMFs mean moderate levels of intermolecular attraction, allow liquid molecules to flow freely with some restrictions (such as not being able to be too far away from another molecule).
Compounds in solid phase usually have comparatively strong IMFs. Strong IMFs mean high levels of intermolecular attraction, allowing solid molecules to stick together tightly and not move a lot.
Similarly, if a compound has strong IMFs, it usually has a high melting and boiling point. If a compound has weak IMFs, it usually has a low melting and boiling point.
Predicting Phases
It’s impossible to predict the absolute melting or boiling points just by looking at the molecular structure alone. However, it is possible to compare the molecule of interest with other known compounds and see if the molecule will have higher or lower melting or boiling points.
We have 2 factors we need to consider when comparing.
Given similar types of IMFs present between molecules, what is the amount of IMFs present in the molecule?
Given similar amounts of IMFs present between molecules, what are the strengths of the individual IMFs?
Let’s look at 2 examples – $CH_4 \text{vs.} C_2H_6$ and $CH_4 \text{vs.} NH_3$
For $CH_4 \text{vs.} C_2H_6$, we have LDFs for both compounds. However, $C_2H_6$ has bigger surface area, allowing more LDFs present. Thus, $C_2H_6$ should have a higher melting and boiling point than $CH_4$.
For $CH_4 \text{vs.} NH_3$, we have similar amounts of IMFs present because the molecules are of similar sizes. However, $NH_3$ has H-bonding while $CH_4$ only has LDFs. Thus, $NH_3$ should have a higher melting and boiling point than $CH_4$.
Compound
Melting Point (C)
Boiling Point (C)
Phase at 20C
$CH_4$
-182
-162
Gas
$C_2H_6$
-183
-89
Gas
$NH_3$
-78
-33
Gas
C2H6 does have a marginally lower melting point than CH4 when we predicted a higher melting point instead. Exceptions like this are extremely common because there are a lot more factors in play here.
Comparing Substances
Let’s look at groups of compounds and compare them together.
Example 1: n-Alkanes
For our first group, we will look at straight-chain alkanes with increasing numbers of carbons from 1 to 20 (see diagram below for visualization).
As we look at the molecular structures, we can predict that:
The predominant IMF in alkanes is LDFs.
As we increase the number of carbons in alkanes, surface area increases.
As surface area increases, the amount of LDFs between molecules increases.
As more LDFs are present between molecules, IMF increases.
As IMF increases, melting and boiling point should generally increase.
The graph supports our prediction – melting and boiling points increase as we add carbons to alkanes. There are some exceptions, but the prediction works decently.
Using this, we can predict that tetracontane $C_{40}H_{82}$ will have a higher melting point (82 C) and boiling point (525 C).
Example 1 focuses on the amount of IMFs. Example 2, on the other hand, will focus on the types of IMFs, given similar amounts of IMFs present. We will, of course, encounter exceptions along the way.
Example 2: IMF Strength across Periodic Table Period
Let’s look at several groups, starting with the basic ones. We will go from left to right in the periodic table.
Molecule
Melting Point (C)
Boiling Point (C)
$CH_4$
-182
-162
$NH_3$
-78
-33
$H_2O$
0
100
$HF$
-84
20
HF is clearly the exception here.
The first 3 molecules make sense – the IMFs get stronger and stronger, so the melting and boiling points increase. However, $HF$, having the most electronegative element, has a significantly lower melting and boiling points compared to $H_2O$. This exception can be attributed to the following reason.
$H_2O$ is bigger than $HF$, meaning that $H_2O$ has more places to have hydrogen bonds with.
Let’s look at another group.
Molecule
Melting Point (C)
Boiling Point (C)
$SiH_4$
-185
-112
$PH_3$
-133
-88
$H_2S$
-86
-60
$HCl$
-114
-85
HCl is clearly the exception here.
Similarly, we see an increase in melting and boiling points for the first 3 molecules just for them to dip at $HCl$. The reason is the same – $HCl$ is smaller than $H_2S$, meaning there are fewer amounts of IMFs between $HCl$ than those between $H_2S$ despite $Cl$ being a more electronegative element.
Below are the graphs for those 2 groups of molecules for better visualization.
Data obtained from Wikipedia.
Let’s also look at how hydrogen bonding can influence melting and boiling points. In the previous example, we move from left to right in the periodic table. In this example, we will move from up to down in the periodic table.
Example 3: IMF Strength across Periodic Table Group
Let’s look at 2 groups of molecules as well.
Molecule
Melting Point (C)
Boiling Point (C)
$H_2O$
0
100
$H_2S$
-86
-60
$H_2Se$
-66
-41
$H_2Te$
-49
-2
H2O is clearly the exception here.
As we can see, $H_2O$ has higher melting and boiling points compared to $H_2S, H_2Se, H_2Te$. Since $H_2S, H_2Se, H_2Te$ have a predominant D-D IMF, their melting and boiling points increase as their surface area increases. However, $H_2O$ has hydrogen bonding as their predominant IMF, which is stronger than D-D. As a result, $H_2O$ has higher melting and boiling points compared to other molecules from the same group.
Let’s look at another group.
Molecule
Melting Point (C)
Boiling Point (C)
$HF$
-84
20
$HCl$
-114
-85
$HBr$
-87
-67
$HI$
-51
-35
HF is clearly the exception here.
Here, we have the same reasoning. $HCl, HBr, HI$ all have predominant D-D IMF, and their increasing surface areas imply more IMF interactions, leading to higher melting and boiling points. However, $HF$ has H-bonding as the predominant IMF, which is stronger than D-D. As a result, $HF$ has a higher melting and boiling points compared to $HCl$.
Of course, the strength of predominant IMFs and the amount of IMFs are competing factors here.
For $HF$, its melting point is actually lower than $HI$ despite having a stronger type of IMF. It’s likely because $HI$ has a larger amount of IMFs due to its high surface area. Recall that $I$ has a larger atomic radius compared to $F$.
Below are the graphs for those 2 groups of molecules for better visualization.
Data obtained from Wikipedia.
Break Time: 10 Minutes
Take a short break!
Written by Johannes Brahms, a German composer in the romantic period (the 1800s) who mastered classical music harmony, his Violin Sonata No. 1 in G major is a deeply emotional and technically demanding work. Composed in 1878, it blends lyrical beauty with intricate textures. The first movement, which is played in this break time, “Vivace ma non troppo,” features a lively, rhythmic dialogue between the violin and piano. The second movement, “Adagio,” is rich in expressive depth, with long, sweeping lines. The third movement, “Allegro,” is vigorous and playful, contrasting the previous one. The sonata showcases Brahms’ mastery of melody and harmony, offering a perfect balance of warmth and complexity in its structure and emotional expression. It is performed by renowned violinst Itzhak Perlman and pianist Vladimir Ashkenazy.
Lecture Content (Part 2)
Let’s practice. There will be 5 groups of molecules below. Each group contains 1 reference molecule and 2 other molecules. Our mission is to complete the following tasks.
Task 1: Identify the predominant IMF in the molecules, including the reference molecule.
Task 2: Identify the amount of IMF that can be present in the molecules compared to the reference molecule.
Use words like “more”, “less”, or “roughly equal”.
Task 3: Predict if the molecules in question will have a higher or lower melting and boiling point compared to the reference molecule.
Use words like “higher”, “lower”, or “roughly equal”.
Similarly, feel free to visualize the molecules in 3D using MolView. This is also a great opportunity to get ourselves more familiar with Lewis structures, especially resonance structures.
How can intramolecular interactions explain intermolecular forces?
What types of IMFs are there and how are they different from each other?
How can IMFs help us predict states of matter (phases)?
2. Lecture Worksheet (TBD)
The lecture worksheet is available as a pdf file below. Remember, practice makes perfect!
You finished the lecture! We’ll definitely slow down on the lectures because these concepts are very important. Also, it takes time for our brain to fully absorb new materials. Don’t forget to review!
Some images (with dots as background) are original creations using canva.com Chemicals and 3D images in black background are created using molview.org or molview.com
The interactive periodic table provides common physical and chemical properties of the elements, as well as important periodic table trends, explanations, and practice problems.
The 3D visualization software is molview.com, with a 2D chemical drawer and a 3D visualizer available, great for Lewis structure and molecular/electron geometry representation.
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